In the fourth test match between India and Australia at the Narendra Modi Stadium in Ahmedabad, Team India skipper Rohit Sharma might make a choice that would shock the Kangaroo side.
The four-Test series between India and Australia has reached its conclusion. Team India took an early lead by winning the first two Tests, but before the series could be wrapped up, the Australian team rebounded and won the third match in Indore by nine wickets.
The last match of the series will be contested at the Narendra Modi Stadium in Ahmedabad, and Team India must win this match to go to the World Cup finals. Team India Captain Rohit Sharma has devised a strategy to defeat the Kangaroos and has suggested that Shardul Thakur may return in the last Test.
Mohammad Siraj is bowling well and has played all three matches, therefore he might be rested in the last match. Mohammed Shami, who had played the previous two Tests, was rested for the third, and Umesh Yadav took his place and bowled superbly.
With Thakur’s inclusion in the starting XI, not only will there be an advantage in bowling, but also in batting depth. Throughout the first three matches, Team India’s lineup has remained mostly unchanged. Akshar Patel bats at number nine, Shardul Thakur adds another batter, while Mohammad Siraj rests ahead of the ODI series.
The last match will be crucial for the Indian team because if it loses, it would have to rely on other teams to make the ICC World Test Championship final, but if it wins, it will be the second team after Australia. The starting Eleven will be released a day before the game when Rohit Sharma speaks to the media, and the announcement will be made before the toss on March 9.
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